document.write( "Question 980590: A metal alloy is 30% nickel. Another metal ally is 70% nickel. The two alloys are mixed to produce 20kg of a metal alloy that is 48% nickel. How much of each metal alloy is used. \n" ); document.write( "
Algebra.Com's Answer #601721 by ikleyn(52817)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let  x  be the mass of the first alloy  (first piece)  in kilograms,  and let  y  be the mass of the second alloy  (second piece)  in kilograms.\r
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\n" ); document.write( "\n" ); document.write( "Then you have first equation \r
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\n" ); document.write( "\n" ); document.write( "x + y = 20.\r
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\n" ); document.write( "\n" ); document.write( "The first alloy contains  0.3*x  kilograms of nickel,  and the second alloy contains  0.7*y  kilograms of nickel.  Therefore the mix contains  0.3*x + 0.7*y  kilograms of nickel. \r
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\n" ); document.write( "\n" ); document.write( "It gives you the second equation\r
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\n" ); document.write( "\n" ); document.write( "0.3*x + 0.7*y = 0.48*20 = 9.6.\r
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\n" ); document.write( "\n" ); document.write( "So,  you have the system of two linear equations in two unknowns\r
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\n" ); document.write( "\n" ); document.write( "\"system%28x+%2B+y+=+20%2C%0D%0A0.3%2Ax+%2B+0.7%2Ay+=+9.6%29\".\r
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\n" ); document.write( "\n" ); document.write( "Solve yourself this system.\r
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