document.write( "Question 980591: Solve equation:\r
\n" ); document.write( "\n" ); document.write( "log base 2 of X plus log base 2 of (3X+1) = 1\r
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\n" ); document.write( "\n" ); document.write( "Answer in my book says, 2/3
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Algebra.Com's Answer #601714 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"log%282%2C%28x%29%29%2Blog%282%2C%283x%2B1%29%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%282%2C%28x%2A%283x%2B1%29%29%29=1\" Use rule 1\r
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\n" ); document.write( "\n" ); document.write( "\"x%2A%283x%2B1%29=2%5E1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2A%283x%2B1%29=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2%2Bx=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2%2Bx-2=0\"\r
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\n" ); document.write( "\n" ); document.write( "Use the quadratic formula to get the solutions \"x+=+2%2F3\" or \"x+=+-1\"\r
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\n" ); document.write( "\n" ); document.write( "The value \"x+=+-1\" is NOT allowed because logs aren't defined when you plug in negative x values\r
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\n" ); document.write( "\n" ); document.write( "The only solution is \"x+=+2%2F3\"\r
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