document.write( "Question 980585: `A train goes from New Orleans to Boston at 40 mph. On the way back it returns with a speed of 80 miles per hour. If it takes one hour less time to return, what is it's average speed? \n" ); document.write( "
Algebra.Com's Answer #601713 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Average speed is always [ total distance ] / [ total time ]
\n" ); document.write( "Let \"+d+\" = distance in miles between New Orleans and Boston
\n" ); document.write( "Let \"+t+\" = time in hrs going from New Orleans to Boston
\n" ); document.write( "\"+t+-+1+\" = time in hrs going from Boston to New Orleans
\n" ); document.write( "-----------------------------------------------------
\n" ); document.write( "Equation for New Orleans to Boston:
\n" ); document.write( "(1) \"+d+=+40t+\"
\n" ); document.write( "Equation for Boston to New Orleans:
\n" ); document.write( "(2) \"+d+=+80%2A%28+t-1+%29+\"
\n" ); document.write( "-----------------------
\n" ); document.write( "[ total distance ] = \"+2d+\"
\n" ); document.write( "--------------------------------------
\n" ); document.write( "(1) \"+t+=+d%2F40+\"
\n" ); document.write( "(2) \"+d+=+80%2A%28+t-1%29+\"
\n" ); document.write( "(2) \"+t-1+=+d%2F80+\"
\n" ); document.write( "---------------------------------
\n" ); document.write( "[ total time ] = \"+t+%2B+t-1+=+d%2F40+%2B+d%2F80+\"
\n" ); document.write( "------------------------
\n" ); document.write( "[ total distance ] / [ total time ] = \"+%28+2d+%29+%2F+%28+d%2F40+%2B+d%2F80+%29+\"
\n" ); document.write( "Divide top and bottom by \"+d+\"
\n" ); document.write( "\"+2+%2F+%28+1%2F40+%2B+1%2F80+%29+\"
\n" ); document.write( "Multiply top and bottom by \"+80+\"
\n" ); document.write( "\"+160+%2F+%28+2+%2B+1+%29+=+53.333+\" mi/hr
\n" ); document.write( "--------------------------------
\n" ); document.write( "Note that you do not take the average of the two averages
\n" ); document.write( "which would be: \"+%28+40+%2B+80+%29+%2F+2+=+60+\" mi/hr\r
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