document.write( "Question 980560: Solver the given trig equation exactly on 0<=theta<2pi\r
\n" ); document.write( "\n" ); document.write( "question is: 2cos(theta/2)= -sqrt2\r
\n" ); document.write( "\n" ); document.write( "So far I divided the 2 on the left and the right side of the equation leaving me with, Cos(theta/2)= -sqrt2/2
\n" ); document.write( "Now, I'm lost...\r
\n" ); document.write( "\n" ); document.write( "(this is a pre-cal question. The topic list is blank for me. Sorry)
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Algebra.Com's Answer #601694 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Solver the given trig equation exactly on 0<=theta<2pi\r
\n" ); document.write( "\n" ); document.write( "question is: 2cos(theta/2)= -sqrt2\r
\n" ); document.write( "\n" ); document.write( "So far I divided the 2 on the left and the right side of the equation leaving me with, Cos(theta/2)= -sqrt2/2
\n" ); document.write( "------------
\n" ); document.write( "Use the double angle formula:
\n" ); document.write( "cos(2t) = 2cos^2(t) - 1
\n" ); document.write( "= 2*(1/2) - 1
\n" ); document.write( "cos(theta) = 0
\n" ); document.write( "----
\n" ); document.write( "theta = pi/2, 3pi/2\r
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