document.write( "Question 980546: \"Police arrive at a murder scene at 3:00 AM and record the bodes temperature which was 93F. aT 4:00 AM, after inspecting and fingerprinting the area, they again took the temperature of the body which dropped to 82F. The temperature of the crime scene has remained at a constant 71F. Determine when the person was murdered. Assume that the temperature of the body at the time of death was 98.6F.\"\r
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\n" ); document.write( "i really need any help for this problem, i have no idea how to solve to get the final answer.
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Algebra.Com's Answer #601671 by macston(5194)\"\" \"About 
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If the decrease in body temperature is linear, then the temperature drops at a rate of 9 degrees F per hour (from 93F at 3:00AM to 82F at 4:00AM)
\n" ); document.write( "From the time of death (body at 98.6F) to 3:00AM (body at 93F), the temperature has dropped (98.6F-93F=5.6F) 5.6 degrees F.
\n" ); document.write( "\"5.6F%2F%289F%2Fhr%29=0.622hr\"
\n" ); document.write( "\"%280.622hr%29%2860min%2Fhr%29=37.3min\"
\n" ); document.write( "At 3:00AM, the body has been dead for 37 minutes, so time of death was 2:27AM
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