document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83685>Question 83685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Multiply: (x/3+3/4)(3x/4-3/5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60167 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60167\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X/3+3/4<BR>\n" );
document.write( "3X/4-3/5<BR>\n" );
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document.write( "(X/3)(3X/4)+(3/4)(3X/4)+(X/3)(-3/5)+(3/4)(-3/5)<BR>\n" );
document.write( "3X^2/12+9X/16-3X/15-9/20 NOW FIND A COMMON DENOMINATOR SO WE CAN ADD THESE FRACTIONS THUS: WE HAVE A LOWEST COMMON DENOMINATOR OF 240:<BR>\n" );
document.write( "(3X^2*10+9X*15-3X*16-9*12)/240<BR>\n" );
document.write( "(30X^2+135X-48X-108)/240<BR>\n" );
document.write( "(30X^2+87X-108)/240 NOW REDUCE BY DIVIDING BY 3:<BR>\n" );
document.write( "(10X^2+29X-36)/80 THE NUMERATOR CAN ONLY BE REDUCED USING THE QUADRATIC EQUATION.<BR>\n" );
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