document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=980537>Question 980537</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi there! \r<BR>\n" );
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document.write( "My question is: Find 83 2/3 % of 12.6\r<BR>\n" );
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document.write( "This website shows how to do this problem, but I am having trouble understanding it. Could anyone please break it down and explain step by step what the process is without the usage of a calculator.\r<BR>\n" );
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document.write( "It is example 4 on this page: <BR>\n" );
document.write( "http://amby.com/educate/math/4-2_prop.html\r<BR>\n" );
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document.write( "What I don't understand most is how they got 126/10 and 251/3. Where are the denominators of those fractions coming from? I do know how 251 came about (from the 83 & 2/3). What I have done is set up my equation exactly like the site has however I thought you have  to multiply 12.6 (251) divided by 100 to get x. Please help!\r<BR>\n" );
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document.write( "Thanks in advance!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #601665 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=601665\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find 83 2/3 % of 12.6<BR>\n" );
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document.write( "83 2/3 % = 251/3 %<BR>\n" );
document.write( "% = per hundred<BR>\n" );
document.write( "--> (251/3)/100<BR>\n" );
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document.write( "12.6*(251/3)/100 = 10.542 </SPAN>\n" );
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