document.write( "Question 980537: Hi there! \r
\n" ); document.write( "\n" ); document.write( "My question is: Find 83 2/3 % of 12.6\r
\n" ); document.write( "\n" ); document.write( "This website shows how to do this problem, but I am having trouble understanding it. Could anyone please break it down and explain step by step what the process is without the usage of a calculator.\r
\n" ); document.write( "\n" ); document.write( "It is example 4 on this page:
\n" ); document.write( "http://amby.com/educate/math/4-2_prop.html\r
\n" ); document.write( "\n" ); document.write( "What I don't understand most is how they got 126/10 and 251/3. Where are the denominators of those fractions coming from? I do know how 251 came about (from the 83 & 2/3). What I have done is set up my equation exactly like the site has however I thought you have to multiply 12.6 (251) divided by 100 to get x. Please help!\r
\n" ); document.write( "\n" ); document.write( "Thanks in advance!!
\n" ); document.write( "

Algebra.Com's Answer #601664 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "Using given method:
\n" ); document.write( ".
\n" ); document.write( "\"x%2F12.6=%2883%2B2%2F3%29%2F100\"
\n" ); document.write( ".
\n" ); document.write( "Convert mixed fractions and decimals to improper fractions.
\n" ); document.write( "12.6 = 12 6/10 = 126/10 This denominator from tenths in the decimal.
\n" ); document.write( "83 2/3 = 251/3 This denominator from thirds in the percent.
\n" ); document.write( ".
\n" ); document.write( "\"x%2F%28126%2F10%29=%28251%2F3%29%2F100\" Cross multiply
\n" ); document.write( ".
\n" ); document.write( "\"100x=%28126%2F10%29%28251%2F3%29\"
\n" ); document.write( ".
\n" ); document.write( "\"100x=31626%2F30\" Divide each side by 100.
\n" ); document.write( "\"x=31626%2F3000\" Convert right side to thousands,
\n" ); document.write( "multiply by \"%281%2F3%29%2F%281%2F3%29\" (equivalent to 1) to make it easier
\n" ); document.write( "to convert to decimal.
\n" ); document.write( ".
\n" ); document.write( "\"x=10542%2F1000\"
\n" ); document.write( "\"x=10.542\"
\n" ); document.write( ".
\n" ); document.write( "Even by hand (without calculator), I find it quicker to use:
\n" ); document.write( "\"%28.8367%29%2812.6%29=10.542\"
\n" ); document.write( "though the first method avoids any error from rounding.\r
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