document.write( "Question 980509: Good evening, I need a little help in my activity in trigonometry, about linear, angular speed and area of sector of circles, here's the problem.\r
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\n" ); document.write( "\n" ); document.write( "The top and bottom ends of a windshield wiper blade are 34 in. and 14 in. from the pivot point, respectively. While in operation, the wiper sweeps through 135°. Find the area swept by the blade. \n" ); document.write( "
Algebra.Com's Answer #601649 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "Using the formula:
\n" ); document.write( "Angle/360 = area of sector/πr^2
\n" ); document.write( "135/360 = area of sector/π 34^2
\n" ); document.write( "Cross multiply
\n" ); document.write( "360 x area of sector = 135 x π x 1156
\n" ); document.write( "Area of Sector = (135 x π x 1156)/360
\n" ); document.write( "Area of sector = 1361.88 ins^2
\n" ); document.write( "This is the large sector, now we estimate
\n" ); document.write( "the sector from 14 ins downwards
\n" ); document.write( "135/360 = area of sector/π x 14^2
\n" ); document.write( "Cross multiply
\n" ); document.write( "360 x area of sector = 135 x π x 14^2
\n" ); document.write( "Area of sector = 135 x π x 14^2/360
\n" ); document.write( "Area of sector = 230.91 ins^2
\n" ); document.write( "If you now take the area of the small sector
\n" ); document.write( "away from the area of the large sector, what
\n" ); document.write( "is left is the area swept by the blade.
\n" ); document.write( "1361.88 - 230.91 = 1130.97 ins^2
\n" ); document.write( "Hope this helps:-) \n" ); document.write( "
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