document.write( "Question 980507: The price of a shirt was discounted by 20% on Monday, then by another 30% on Tuesday.Its final price on Tuesday represents what percent of a discount from I its original price?
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document.write( "A)33%
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document.write( "B)40%
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document.write( "C)44%
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document.write( "D)50%
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document.write( "E)60%
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Algebra.Com's Answer #601637 by onlinepsa(22)![]() ![]() You can put this solution on YOUR website! In case of successive percentage change 'a' and 'b', the net percentage change is given by:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a + b + (a * b)/100\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here, a= -20; b= -30\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Net percentage change= -20 + -30 + (-20 * -30)/100 = -50 + 6 = - 44\r \n" ); document.write( "\n" ); document.write( "Net discount= 44 %\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Second method:\r \n" ); document.write( "\n" ); document.write( "20% discount is same as multiplying factor 0.80\r \n" ); document.write( "\n" ); document.write( "30% discount is same as multiplying factor 0.70\r \n" ); document.write( "\n" ); document.write( "Net multiplying factor = 0.80 * 0.70\r \n" ); document.write( "\n" ); document.write( "=0.56\r \n" ); document.write( "\n" ); document.write( "Multiplying factor is 0.56; thus the discount is 100 - 56 = 44%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thanks, \n" ); document.write( "PRD \n" ); document.write( "https://onlinepsa.wordpress.com \n" ); document.write( " |