document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=980429>Question 980429</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a father is four times as old as the son now.if the sum of their ages ten years ago was 60,find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #601635 by </B><A HREF=/tutors/aboutme.mpl?userid=Bibin><B>Bibin(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Bibin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=601635\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here 10 years ago sum of ages 60. There for now thier sum of ages equals 60+10+10 = 80<BR>\n" );
document.write( "Ratio of their ages = 4:1 <BR>\n" );
document.write( "Age of father = 80×4/5 =64<BR>\n" );
document.write( "Age of son = 80×1/5 =16 </SPAN>\n" );
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