document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=980493>Question 980493</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please tell me the way on how to solve this step-by-step by finding the roots of this in the form of quadratic equation.\r<BR>\n" );
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document.write( "A=160 meter square<BR>\n" );
document.write( "L=2x+3<BR>\n" );
document.write( "W=x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #601632 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=601632\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L * W = A where L is length, W is width, A is the area<BR>\n" );
document.write( "(2x+3) * (x) = 160<BR>\n" );
document.write( "2x^2 + 3x = 160<BR>\n" );
document.write( "2x^2 + 3x - 160 = 0<BR>\n" );
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document.write( "use quadratic formula<BR>\n" );
document.write( "(-b + or - square root(b^2 - 4ac)) / 2a<BR>\n" );
document.write( "x = (-3 + square root(9 - 4*2*(-160))) / 4 = 320<BR>\n" );
document.write( "x = (-3 - square root(9 - 4*2*(-160))) / 4 = &#8722;321.5<BR>\n" );
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document.write( "there are two solutions<BR>\n" );
document.write( "x = 320 and x = -321.5\r<BR>\n" );
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