document.write( "Question 83637: I have two similiar problems to solve. If I can get help with how to solve one of them, I'm sure I can work the other.
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document.write( "e^(x-8) = 33
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document.write( "3^(4x-3) = 3\r
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Algebra.Com's Answer #60163 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! e^(x-8) = 33 \n" ); document.write( ": \n" ); document.write( "Using nat logs: \n" ); document.write( "ln(e^(x-8)) = ln(33) \n" ); document.write( ": \n" ); document.write( "Log equiv of exponents: \n" ); document.write( "(x-8)*ln(e) = ln(33) \n" ); document.write( ": \n" ); document.write( "Find the ln of both sides. Nat ln of e = 1, remember \n" ); document.write( "x - 8 = 3.4965 \n" ); document.write( "x = 3.4965 + 8 \n" ); document.write( "x = 11.4965 \n" ); document.write( ": \n" ); document.write( "Check solution on a good calc: enter: e^(11.4965-8); should get 32.99975 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "3^(4x-3) = 3 \n" ); document.write( "Just looking at it you know that 4x-3 = 1, but here is the method anyway \n" ); document.write( ": \n" ); document.write( "Using nat logs again \n" ); document.write( "ln(3^(4x-3) = ln(3) \n" ); document.write( ": \n" ); document.write( "(4x-3)*ln (3) = ln(3) \n" ); document.write( "(4x-3)*1.0986 = 1.0986 \n" ); document.write( "4x - 3 = 1.0986/1.0986 \n" ); document.write( "4x - 3 = 1 \n" ); document.write( "4x = 1 + 3 \n" ); document.write( "4x = 4 \n" ); document.write( "x = 4/4 \n" ); document.write( "x = 1 \n" ); document.write( ": \n" ); document.write( "Did this help? \n" ); document.write( " |