document.write( "Question 980312: Felice drove her car 300km at a certain average speed. Had she travelled 10kph faster, the trip would have taken 1 hour less. Find Felice's average speed. \n" ); document.write( "
Algebra.Com's Answer #601611 by ikleyn(52903)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "50 \"km%2Fh\"  and  60 \"km%2Fh\".\r
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\n" ); document.write( "\n" ); document.write( "I solved it momentarily without using equation  (mentally!)\r
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\n" ); document.write( "\n" ); document.write( "OK,  this is a joke :)\r
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\n" ); document.write( "\n" ); document.write( "Now let me solve it with using equations.\r
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\n" ); document.write( "\n" ); document.write( "Let  x  be the Felice's average speed. \r
\n" ); document.write( "\n" ); document.write( "Then she spent  \"300%2Fx\"  hours to cover  300 km.\r
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\n" ); document.write( "\n" ); document.write( "If she'd traveled  10 \"km%2Fh\"  faster, i.e.  \"x+%2B+10\" \"km%2Fh\",  then the trip would take  \"300%2F%28x%2B10%29\",  and it would be in  1  hour less than  \"300%2Fx\".  Thus you have an equation\r
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\n" ); document.write( "\n" ); document.write( "\"300%2Fx\" - \"300%2F%28x%2B10%29\" = 1.\r
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\n" ); document.write( "\n" ); document.write( "Solve this equation simplifying it step by step:\r
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\n" ); document.write( "\n" ); document.write( "300*(x + 10) - 300*x = x*(x +10),\r
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\n" ); document.write( "\n" ); document.write( "300x + 3000 -300x = x^2 + 10x,\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 10x - 3000 = 0.\r
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\n" ); document.write( "\n" ); document.write( "Next, apply the quadratic formula  (see the lesson  Introduction into Quadratic Equations  in this site) \r
\n" ); document.write( "\n" ); document.write( "or the  Viete's theorem  (lesson  Solving quadratic equations without quadratic formula). \r
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\n" ); document.write( "\n" ); document.write( "You will get this answer:  x = 50 \"km%2Fh\". \r
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\n" ); document.write( "\n" ); document.write( "Another root  (x = -60 \"km%2Fh\")  is not applicable. \r
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