document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83648>Question 83648</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hopefully - this is my last question! I'm a little confused on this one, probably because it is a word problem.<BR>\n" );
document.write( "The equation P(a) = 14.7e^-0.21a, where a is the altitude above sea level measured in miles yields the atmospheric pressure in pounds per square inch.  if the atmospheric pressure is apporximately 11.35 pounds per square inch, find that altitude avoe sea level.  Express to the nearest hundred feet. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60160 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60160\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the 11.35 is the P (which is a function of (a)), so you need to find the value of a in the equation\r<BR>\n" );
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document.write( "11.35=14.7e^(-0.21a) ... taking natural log gives, ln(11.35)=ln(14.7)-0.21a\r<BR>\n" );
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document.write( "ln(11.35)-ln(14.7)=(-0.21)a ... (ln(11.35)-ln(14.7))/(-0.21)=a ... a approximately equals 1.232 mi.   </SPAN>\n" );
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