document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83683>Question 83683</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Multiply:  7w(2w-3)(2w+3)...I have attempted to figure this one out, so far I have 14w-3 14w+3...am I right so far? How do I complete this problem? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60158 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60158\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Multiply: 7w(2w-3)(2w+3)\r<BR>\n" );
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document.write( "=7w(4w^2-9)\r<BR>\n" );
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document.write( "=28w^2 - 63w\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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