document.write( "Question 980442: The power produced by a windmill varies directly with the square of its diameter and the cube of the wind speed. A fan with a diameter of 2.5 meters produces 560 watts of power if the wind speed is 4 m/s. How much power would a similar fan produce if it had a diameter of 6 meters and the wind speed was 5 m/s? \n" ); document.write( "
Algebra.Com's Answer #601563 by ikleyn(52842)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The condition of this problem means  exactly the following:\r
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\n" ); document.write( "\n" ); document.write( "The power produced by a windmill  is proportional to the product of the square of its diameter and the cube of the wind speed. \r
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\n" ); document.write( "\n" ); document.write( "In other words, \r
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\n" ); document.write( "\n" ); document.write( "\"P\" = \"k\".\"D%5E2\".\"w%5E3\", \r
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\n" ); document.write( "\n" ); document.write( "where  \"P\"  is the power produced by a windmill,  \"D\"  is a windmill diameter,  \"w\"  is the wind speed,  and  \"k\" is the proportionality coefficient which is the constant value for the selected unit system. \r
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\n" ); document.write( "\n" ); document.write( "Therefore,  the proportion is valid\r
\n" ); document.write( "\n" ); document.write( "\"P%5B2%5D%2FP%5B1%5D\" = \"%28D%5B2%5D%2FD%5B1%5D%29%5E2\".\"%28w%5B2%5D%2Fw%5B1%5D%29%5E3\" = \"%284%2F2.5%29%5E2\".\"%285%2F4%29%5E3\" = \"1.6%5E2\".\"1.25%5E3\" = 2.56*1.953 = 5. \r
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\n" ); document.write( "\n" ); document.write( "where the index  \"1\"  relates to the  \"smaller windmill\",  and the index  \"2\"  relates to the  \"larger windmill\".\r
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\n" ); document.write( "\n" ); document.write( "Finally,  its gives \"P%5B2%5D\" = \"5\".\"P%5B1%5D\" = 5*560 watts = 2800 watts.\r
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