document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=980415>Question 980415</A>: <I><SPAN STYLE=\"word-break: break-all;\"> During normal business hours on the east coast, calls to the toll-free reservation number of the Nite Time Inn arrive at a rate of 5 per minute. It has been determined that the number of calls per minute can be described by the Poisson distribution. Find the probability that in the next minute, the number of calls arriving will be:<BR>\n" );
document.write( "	(a)  Exactly 5<BR>\n" );
document.write( "	(b)  Exactly 4<BR>\n" );
document.write( "	(c)  Exactly 3<BR>\n" );
document.write( "	(d)  Exactly 6<BR>\n" );
document.write( "	(e)  Less than 2<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #601555 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=601555\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(5) with Poisson parameter 5.  It is e^(-lambda) *Lambda^5 (or whatever number x is)/x!<BR>\n" );
document.write( "exp(-5)*5^5/5!=0.1755  This is the expected value. Also, the variance is 5 as well.  <BR>\n" );
document.write( "exp(-5)5^4/4!=0.1755<BR>\n" );
document.write( "exp(-5)5^3/3!=0.1404<BR>\n" );
document.write( "exp(-5)5^6/6!=0.1462<BR>\n" );
document.write( "That is 1 and 0<BR>\n" );
document.write( "exp(-5)*5=0.0337 + exp(-5)=0.0067 and that sum is 0.0404.<BR>\n" );
document.write( "!=1  0!=1 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );