document.write( "Question 980386: The area of a rectangle is 42 m^2, and the length of the rectangle is 5 m more than double the width. Find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #601534 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "Make the width 'x'
\n" ); document.write( "Length = 5 + 2x
\n" ); document.write( "Area = Length x Width
\n" ); document.write( "42 = (5 + 2x)x
\n" ); document.write( "42 = 5x + 2x^2
\n" ); document.write( "Sort into ax^2 + bx + c = 0
\n" ); document.write( "2x^2 + 5x - 42 = 0
\n" ); document.write( "Factorise
\n" ); document.write( "(2x - 7)(x + 6)= 0
\n" ); document.write( "x + 6 = 0
\n" ); document.write( "x = -6 (No answer as -ve)
\n" ); document.write( "2x - 7 = 0
\n" ); document.write( "2x = 7
\n" ); document.write( "x = 7/2 or 3.5
\n" ); document.write( "Width = 3.5m
\n" ); document.write( "Length = 12m
\n" ); document.write( "Hope this helps:-)
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