document.write( "Question 980386: The area of a rectangle is 42 m^2, and the length of the rectangle is 5 m more than double the width. Find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #601534 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Make the width 'x' \n" ); document.write( "Length = 5 + 2x \n" ); document.write( "Area = Length x Width \n" ); document.write( "42 = (5 + 2x)x \n" ); document.write( "42 = 5x + 2x^2 \n" ); document.write( "Sort into ax^2 + bx + c = 0 \n" ); document.write( "2x^2 + 5x - 42 = 0 \n" ); document.write( "Factorise \n" ); document.write( "(2x - 7)(x + 6)= 0 \n" ); document.write( "x + 6 = 0 \n" ); document.write( "x = -6 (No answer as -ve) \n" ); document.write( "2x - 7 = 0 \n" ); document.write( "2x = 7 \n" ); document.write( "x = 7/2 or 3.5 \n" ); document.write( "Width = 3.5m \n" ); document.write( "Length = 12m \n" ); document.write( "Hope this helps:-) \n" ); document.write( " |