document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83654>Question 83654</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble with this homeowrk question which states:  Solve 2x^2-8x+1=0 by completing the square.  So far I have 1/2(2x^2-8x)=1/2(-1)        <BR>\n" );
document.write( "                                                       x^2-4x=-1/2<BR>\n" );
document.write( "What now?!? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60153 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60153\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> take half of the coefficient of the x term, square it, and add (to both sides) ... then factor, and take square root\r<BR>\n" );
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document.write( "x^2-4x+(-2)^2=(-1/2)+(-2)^2 ... x^2-4x+4=7/2 ... (x-2)^2=7/2 ... <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x-2=sqrt%287%2F2%29 ALIGN=MIDDLE  ALT=\"x-2=sqrt%287%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > ... <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%282+%2B-+sqrt%287%2F2%29%29 ALIGN=MIDDLE  ALT=\"x=%282+%2B-+sqrt%287%2F2%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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