document.write( "Question 980379: A father is 60 years old and his son is half his age. How old was the boy when his father was four times his age? \n" ); document.write( "
Algebra.Com's Answer #601512 by macston(5194)\"\" \"About 
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\n" ); document.write( "F=father's age; S=son's age; x=years ago father's age=4 times son's age
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\n" ); document.write( "F=2S
\n" ); document.write( "60=2S
\n" ); document.write( "30=S Son is 30 years old.
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\n" ); document.write( "F-x=4(S-x)
\n" ); document.write( "60-x=4(30-x)
\n" ); document.write( "60-x=120-4x
\n" ); document.write( "3x=60
\n" ); document.write( "x=20 Father was 4 times as old as son 20 years ago.
\n" ); document.write( ".
\n" ); document.write( "Son is now 30, 20 years ago he was 30-20=10 years old.
\n" ); document.write( "ANSWER: The son was 10 years old when his father was four times his age.
\n" ); document.write( "(Father is now 60, so Father was 60-20=40 years old.)
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