document.write( "Question 980379: A father is 60 years old and his son is half his age. How old was the boy when his father was four times his age? \n" ); document.write( "
Algebra.Com's Answer #601512 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "F=father's age; S=son's age; x=years ago father's age=4 times son's age \n" ); document.write( ". \n" ); document.write( "F=2S \n" ); document.write( "60=2S \n" ); document.write( "30=S Son is 30 years old. \n" ); document.write( ". \n" ); document.write( "F-x=4(S-x) \n" ); document.write( "60-x=4(30-x) \n" ); document.write( "60-x=120-4x \n" ); document.write( "3x=60 \n" ); document.write( "x=20 Father was 4 times as old as son 20 years ago. \n" ); document.write( ". \n" ); document.write( "Son is now 30, 20 years ago he was 30-20=10 years old. \n" ); document.write( "ANSWER: The son was 10 years old when his father was four times his age. \n" ); document.write( "(Father is now 60, so Father was 60-20=40 years old.) \n" ); document.write( " |