document.write( "Question 980377: questions
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document.write( "(1) If the probability of an event NOT happening is 0.06 what is the probability of it happening?\r
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document.write( "(2)Evaluate 10C3?\r
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document.write( "(3)if a teacher grades distribution is over 3 years what are empirical probability for some to get A,C,D when A=39, C=258, and D=124?\r
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document.write( "(4)If there are 984 flower which 632 are white and 352 are purple what is the probability that you will pick a white flower? \n" );
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Algebra.Com's Answer #601508 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! The probabilities have to add to 1 \n" ); document.write( "If one is 0.06, the other has to be (1-0.06)=0.94\r \n" ); document.write( "\n" ); document.write( "10C3= \n" ); document.write( "10!/7!3! \n" ); document.write( "10*9*8*7!/7!*3*2*1\r \n" ); document.write( "\n" ); document.write( "The 7! cancel \n" ); document.write( "10*9*8/3*2*1 \n" ); document.write( "720/6=120 \n" ); document.write( "======= \n" ); document.write( "Three are 421 outcomes \n" ); document.write( "A=39/421 =0.0926 \n" ); document.write( "C=258/421=0.6128 \n" ); document.write( "D=124/421=0.2945 \n" ); document.write( "That adds up to 0.9999. \n" ); document.write( "====== \n" ); document.write( "632/(632+352) \n" ); document.write( "632/984 \n" ); document.write( "0.6423\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |