document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=980353>Question 980353</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the angle if its complement is 40 degrees less than one half of its supplement.<BR>\n" );
document.write( "A:45 Degrees<BR>\n" );
document.write( "B:55 Degrees<BR>\n" );
document.write( "C:65 Degrees<BR>\n" );
document.write( "D:70 Degrees<BR>\n" );
document.write( "E:80 Degrees </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #601504 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=601504\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x is the angle<BR>\n" );
document.write( "complement is (90-x)<BR>\n" );
document.write( "supplement is (180-x)<BR>\n" );
document.write( "Therefore, (90-x)+40=(1/2)(180-x)<BR>\n" );
document.write( "90-x+40=90 -(1/2)x<BR>\n" );
document.write( "(x/2)=40<BR>\n" );
document.write( "x=80 degrees<BR>\n" );
document.write( "complement is 10 degrees<BR>\n" );
document.write( "supplement is 100 degrees; half the supplement is 50 degrees, and 40 less is 10 degrees as a check.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );