document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=980353>Question 980353</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the angle if its complement is 40 degrees less than one half of its supplement.<BR>\n" );
document.write( "A:45 Degrees<BR>\n" );
document.write( "B:55 Degrees<BR>\n" );
document.write( "C:65 Degrees<BR>\n" );
document.write( "D:70 Degrees<BR>\n" );
document.write( "E:80 Degrees </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #601503 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=601503\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "X=the angle; 90-X=complement; 180-X=supplement<BR>\n" );
document.write( ".<BR>\n" );
document.write( "(90-X)+40=(1/2)(180-X)<BR>\n" );
document.write( "130-X=90-(1/2)X Subtract 90 from each side.<BR>\n" );
document.write( "40-X=-(1/2)X Add X to each side.<BR>\n" );
document.write( "40=(1/2)X Multiply each side by 2.<BR>\n" );
document.write( "80=X ANSWER: The angle is 80 degrees.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );