document.write( "Question 980310: The length of a rectangular lot is 4m (meters) longer than the width. If the area of the lot is 12m^2, what are its dimensions? \n" ); document.write( "
Algebra.Com's Answer #601501 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "Make width = 'x'
\n" ); document.write( "Length = 4 + x
\n" ); document.write( "Area of a rectangle
\n" ); document.write( "= Length x Width
\n" ); document.write( "12m^2 = (4 + x)x
\n" ); document.write( "12m^2 = 4x + x^2
\n" ); document.write( "Put in ax^2 + bx^2 + c = 0 form
\n" ); document.write( "x^2 + 4x - 12 = 0
\n" ); document.write( "Factorise
\n" ); document.write( "(x + 6)(x - 2)= 0
\n" ); document.write( "x + 6 = 0
\n" ); document.write( "x= -6 (No answer as -ve)
\n" ); document.write( "x - 2 = 0
\n" ); document.write( "x = 2
\n" ); document.write( "Therefore:
\n" ); document.write( "Width = 2m
\n" ); document.write( "Length = 6m
\n" ); document.write( "Hope this helps:-)
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