document.write( "Question 980310: The length of a rectangular lot is 4m (meters) longer than the width. If the area of the lot is 12m^2, what are its dimensions? \n" ); document.write( "
Algebra.Com's Answer #601501 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Make width = 'x' \n" ); document.write( "Length = 4 + x \n" ); document.write( "Area of a rectangle \n" ); document.write( "= Length x Width \n" ); document.write( "12m^2 = (4 + x)x \n" ); document.write( "12m^2 = 4x + x^2 \n" ); document.write( "Put in ax^2 + bx^2 + c = 0 form \n" ); document.write( "x^2 + 4x - 12 = 0 \n" ); document.write( "Factorise \n" ); document.write( "(x + 6)(x - 2)= 0 \n" ); document.write( "x + 6 = 0 \n" ); document.write( "x= -6 (No answer as -ve) \n" ); document.write( "x - 2 = 0 \n" ); document.write( "x = 2 \n" ); document.write( "Therefore: \n" ); document.write( "Width = 2m \n" ); document.write( "Length = 6m \n" ); document.write( "Hope this helps:-) \n" ); document.write( " |