document.write( "Question 980356: normal distribution to approximate a binomial distribution.\r
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\n" ); document.write( "\n" ); document.write( "2,881 adults were selected for a survey. if the probability, p, of a response to the survey is 71.85% what would be the probability that 2,086 or less adults would respond to the survey?
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Algebra.Com's Answer #601497 by Boreal(15235)\"\" \"About 
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The point estimate is 0.72405
\n" ); document.write( "1 sample proportion test.
\n" ); document.write( "z=(0.72405-0.7186)/sqrt{ (.7185)(.2815)/2881}
\n" ); document.write( "standard error is 0.00837
\n" ); document.write( "The numerator is 0.005454
\n" ); document.write( "The quotient is z=+0.651
\n" ); document.write( "Probability of anything being less than z=0.6516 in a normal distribution is 0.743.\r
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