document.write( "Question 980356: normal distribution to approximate a binomial distribution.\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "2,881 adults were selected for a survey. if the probability, p, of a response to the survey is 71.85% what would be the probability that 2,086 or less adults would respond to the survey? \n" );
document.write( "
Algebra.Com's Answer #601497 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! The point estimate is 0.72405 \n" ); document.write( "1 sample proportion test. \n" ); document.write( "z=(0.72405-0.7186)/sqrt{ (.7185)(.2815)/2881} \n" ); document.write( "standard error is 0.00837 \n" ); document.write( "The numerator is 0.005454 \n" ); document.write( "The quotient is z=+0.651 \n" ); document.write( "Probability of anything being less than z=0.6516 in a normal distribution is 0.743.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |