document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=980320>Question 980320</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 60 inches and the area is 161 square inches. Find the dimensions of the rectangle<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #601482 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=601482\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> area(A) = l * w where l is length and w is width<BR>\n" );
document.write( "we are given l * w = 161, therefore<BR>\n" );
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document.write( "we ask \"what are the prime factors of 161\"?<BR>\n" );
document.write( "161's prime factors are 7 and 23, that is 7 * 23 = 161<BR>\n" );
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document.write( "Perimeter = 2l + 2w<BR>\n" );
document.write( "let l = 23 and w = 7, then<BR>\n" );
document.write( "60 = 46 + 14<BR>\n" );
document.write( "60 = 60<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "the dimensions of the rectangle are<BR>\n" );
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document.write( "length = 23 inches and width = 7 inches<BR>\n" );
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