document.write( "Question 980287: Chris invests a total of $31,000 in two accounts paying 15% and 7% annual interest, respectively. How much was invested in each account if, after one year, the total interest was $3,290.00.\r
\n" ); document.write( "\n" ); document.write( "$ was invested at 15% and
\n" ); document.write( "$ was invested at 7%. \n" ); document.write( "
Algebra.Com's Answer #601456 by macston(5194)\"\" \"About 
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\n" ); document.write( "F=amount at 15%; S=amount at 7%
\n" ); document.write( "F+S=$31000
\n" ); document.write( "S=$31000-F Use this to substitute for S below.
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\n" ); document.write( "0.07S+0.15F=$3290 Substitute for S from above.
\n" ); document.write( "0.07($31000-F)+0.15F=$3290
\n" ); document.write( "$2170-0.07F+0.15F=$3290
\n" ); document.write( "0.08F=$1120
\n" ); document.write( "F=$14000 ANSWER 1: $14000 was invested at 15%.
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\n" ); document.write( "S=$31000-$14000
\n" ); document.write( "S=$17000 ANSWER 2: $17000 was invested at 7%.
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\n" ); document.write( "CHECK:
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\n" ); document.write( "0.07S+0.15F=$3290
\n" ); document.write( "0.07($17000)+0.15($14000)=$3290
\n" ); document.write( "$1190+$2100=$3290
\n" ); document.write( "$3290=$3290\r
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