document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=980290>Question 980290</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Juan invests a total of $28,500 in two accounts. The first account earned a rate of return of 10% (after a year). However, the second account suffered a 7% loss in the same time period. At the end of one year, the total amount of money gained was $-380.00. How much was invested into each account?\r<BR>\n" );
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document.write( "$ was invested at 10% and<BR>\n" );
document.write( "$ was invested at 7%. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #601455 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=601455\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> amount into first =x<BR>\n" );
document.write( "amount into second=28,500-x\r<BR>\n" );
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document.write( ".10x - .07(28500-x)=-380<BR>\n" );
document.write( ".10x-1995+.07x= -380<BR>\n" );
document.write( ".17x= 1615<BR>\n" );
document.write( "x=9500; 10% interest gives + $950.<BR>\n" );
document.write( "28500-x=19000<BR>\n" );
document.write( "19000*-0.07= -1330\r<BR>\n" );
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document.write( "Difference is -$380 </SPAN>\n" );
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