document.write( "Question 980208: good day\r
\n" ); document.write( "\n" ); document.write( "sorry could not find Calculus in the list. It's differentiation.\r
\n" ); document.write( "\n" ); document.write( "Calculate the turning points\r
\n" ); document.write( "\n" ); document.write( "3x³ - 6x² -9 = 0\r
\n" ); document.write( "\n" ); document.write( "The answers are (0:9) and (4/3:-12.55)\r
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Algebra.Com's Answer #601398 by ikleyn(52786)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "The turning point of a function is the point where the derivative of the function is equal to zero.\r
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\n" ); document.write( "\n" ); document.write( "The derivative of the function  \"y\" = \"3x%B3+-+6x%B2+-9\"  is  \"3%2A3x%5E2+-+6%2A2x\" = \"9x%5E2+-+12x\". \r
\n" ); document.write( "\n" ); document.write( "So,  its turning points are those where the coordinate  (variable)  x satisfies the equation \r
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\n" ); document.write( "\n" ); document.write( "\"9x%5E2+-+12x\" = \"0\".\r
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\n" ); document.write( "\n" ); document.write( "They are  \"x%5B1%5D\" = \"0\"  and  \"x%5B2%5D\" = \"12%2F9\" = \"4%2F3\". \r
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\n" ); document.write( "\n" ); document.write( "The points  (\"x%5B1%5D\",\"f%28x%5B1%5D%29\")  and  (\"x%5B2%5D\",\"f%28x%5B2%5D%29\")  are yours turning points.\r
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\n" ); document.write( "\n" ); document.write( "Calculate yourself the values of  \"f%28x%5B1%5D%29\"  and  \"f%28x%5B2%5D%29\".\r
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