document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=96220>Question 96220</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an army of soldiers is marching down a road at 5 mph. a messenger on horseback rides from the front to the rear and returns immediately, the total time taken being 10 minutes. assuming that the messenger rides at the rate of 10 mph, determine the distance from the front to the rear. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #601374 by </B><A HREF=/tutors/aboutme.mpl?userid=aajayunlimited><B>aajayunlimited(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=aajayunlimited><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=601374\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I noticed that you could eliminate the ft/min step. ankor was right, but it gets even simpler. Formula needed: t = d / r.  | Then, d / r[a] + d / r[b] = t. | Fill in for \"r\" and \"t\". |  d/10 - 5 + d/10 + 5 = 10 minutes. | Convert 10 minutes to 1/6 hrs. | Next, d/5 + d/15 = 1/6.  | Multiply each part by 30 to get rid of fractions. | Now, the equation becomes 6d + 2d = 5 | Last, solve: d = 5/8 of a mi. JUST ADDING TO ANKOR(A SIMPLIER METHOD)--THIS PROBLEM WAS ALREADY SOLVED IN A SIMILIAR FASHION BY ANKOR@DIXIE.NET. </SPAN>\n" );
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