document.write( "Question 980150: The price p and quantity x sold of a small flat screen television set obeys the demand equation below.
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document.write( " p= - .14x+280
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document.write( " a. How much should be charged for the television set if there are 60 television sets in stock? Round to nearest cent
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document.write( " b. What quantity x will maximize revenue? What is the maximum revenue?
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document.write( " c. What price should be charged in order to maximize revenue?
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Algebra.Com's Answer #601369 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The price p and quantity x sold of a small flat screen television set obeys the demand equation below. \n" ); document.write( "p= - .14x+280 \n" ); document.write( ": \n" ); document.write( "a. How much should be charged for the television set if there are 60 television sets in stock? Round to nearest cent \n" ); document.write( "p = -.14(60) + 280 \n" ); document.write( "p = -8.4 + 280 \n" ); document.write( "p = $271.60 \n" ); document.write( ": \n" ); document.write( "b. What quantity x will maximize revenue? \n" ); document.write( "Rev = qty * price \n" ); document.write( "R(x) = x(-.14x+280) \n" ); document.write( "R(x) -.14x^2 + 280x \n" ); document.write( "The axis of symmetry is the qty for max revenue;x = -b/(2a) \n" ); document.write( "x = \n" ); document.write( "x = + 1000 tv's for max rev \n" ); document.write( ": \n" ); document.write( " What is the maximum revenue? \n" ); document.write( "rev = -.14(1000^2) + 280(1000) \n" ); document.write( "rev = -140000 + 280000 \n" ); document.write( "rev = $140,000 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "c. What price should be charged in order to maximize revenue? \n" ); document.write( "p = -.14x + 280 \n" ); document.write( "p = -.14(1000) + 280 \n" ); document.write( "p = -140 + 280 \n" ); document.write( "p = $140 \n" ); document.write( " |