document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83577>Question 83577</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the perimeter of the rectangle in simplified form.  remember that  the formula for perimeter of a rectangle is P=2L+2W\r<BR>\n" );
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document.write( "5 square rooot of 7 +2 square root of 3\r<BR>\n" );
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document.write( "this is the information above the rectangle\r<BR>\n" );
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document.write( "6 square root of 7-3 square root of 3; this information is on the right side of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60131 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60131\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Length of the rectangle = 5 square rooot of 7 +2 square root of 3\r<BR>\n" );
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document.write( "                        = 5sqrt(7) + 2 sqrt(3)\r<BR>\n" );
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document.write( "Width of the rectangle = 6 square root of 7-3 square root of 3\r<BR>\n" );
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document.write( "                       = 6sqrt(7) - 3 sqrt(3)\r<BR>\n" );
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document.write( "Perimeter of the rectangle = 2L + 2W\r<BR>\n" );
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document.write( "                            = 2(5sqrt(7) + 2 sqrt(3)) + 2(6sqrt(7) - 3 sqrt(3))\r<BR>\n" );
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document.write( "                            = 10 sqrt(7) + 4 sqrt(3) + 12 sqrt(7) - 6 sqrt(3)\r<BR>\n" );
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document.write( "                            = 22 sqrt(7) - 2 sqrt(3)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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