document.write( "Question 980091: The area of a triangle is 39 square ft. The length of one side is 1 ft more than teice the altitude to that side. Find the length of that side and the altitude to the side. \n" ); document.write( "
Algebra.Com's Answer #601304 by josh_jordan(263)\"\" \"About 
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To solve this, we first need to know the formula for the area of a triangle:\r
\n" ); document.write( "\n" ); document.write( "\"A=%28bh%29%2F2\", where A is Area, b is base (length of one side), and h is height (altitude)\r
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\n" ); document.write( "\n" ); document.write( "We are told that the length of one side (base) is 1 ft more than twice the altitude. In other words b = 2h + 1\r
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\n" ); document.write( "\n" ); document.write( "Now, let's replace b in our formula for the area of a triangle with 2h + 1, and A with 39, since that's the area of the triangle:\r
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\n" ); document.write( "\n" ); document.write( "\"%28%282h%2B1%29%28h%29%29%2F2=39\"\r
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\n" ); document.write( "\n" ); document.write( "We can now solve for h (altitude). First, multiply both sides of this equation by 2, which will give us\r
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\n" ); document.write( "\n" ); document.write( "(2h + 1)(h) = 39 x 2 -----> (2h + 1)(h) = 78\r
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\n" ); document.write( "\n" ); document.write( "Next, multiply (2h + 1) by (h), giving us\r
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\n" ); document.write( "\n" ); document.write( "\"2h%5E2%2Bh=78\"\r
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\n" ); document.write( "\n" ); document.write( "Third, subtract 78 from both sides and enter a 0 on the right side of the equal sign:\r
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\n" ); document.write( "\n" ); document.write( "\"2h%5E2%2Bh-78=0\"\r
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\n" ); document.write( "\n" ); document.write( "Fourth, factor this quadratic equation, which will give us:\r
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\n" ); document.write( "\n" ); document.write( "\"%282h%2B13%29%28h-6%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "Fifth, set each set of parentheses equal to zero and solve for both values of h:\r
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\n" ); document.write( "\n" ); document.write( "\"2h%2B13=0\"----->\"2h=-13\"----->\"h=-13%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"h-6=0\"----->\"h=6\"\r
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\n" ); document.write( "\n" ); document.write( "Since the height of a triangle cannot be a negative number, we can discard -13/2. So, our altitude (height) is 6 feet.\r
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\n" ); document.write( "\n" ); document.write( "To find our length (base), replace the h in 2h + 1 with 6 and compute:\r
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\n" ); document.write( "\n" ); document.write( "\"2%286%29%2B1\"----->\"12%2B1\"----->\"13\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the length of this triangle is 13 feet and the altitude is 6 feet.
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