document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83585>Question 83585</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor each of the following trinomial completely please with a step by step explanation so I can understand what you did and how you did it. Thank You\r<BR>\n" );
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document.write( "2a^3 - 52a^2 b + 96ab^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60130 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60130\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The given expression is 2a^3-52a^2b+96ab^2\r<BR>\n" );
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document.write( "As a is common to all the terms, remove it out.\r<BR>\n" );
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document.write( "= a(2a^2 - 52ab + 96b^2)\r<BR>\n" );
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document.write( "Now find 2 numbers whose product = 2 x 96 = 192 and whose sum = - 52\r<BR>\n" );
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document.write( "On trying out, w find the numbers as - 48 and - 4\r<BR>\n" );
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document.write( "= a(2a^2 - 4ab - 48ab + 96 b^2) [splitting the middle term]\r<BR>\n" );
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document.write( "= a[2a(a - 2b) - 48b(a - 2b)]\r<BR>\n" );
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document.write( "= a(a - 2b) ( 2a - 48b)\r<BR>\n" );
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document.write( "= a(a - 2b)*2(a - 24 b)\r<BR>\n" );
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document.write( "= 2a(a - 2b)(a - 24b) </SPAN>\n" );
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