document.write( "Question 980079: A told B \" I am thrice as old as you were when I was as old as you are\"... If the sum of their present ages is 25... Find their present ages...... \n" ); document.write( "
Algebra.Com's Answer #601293 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
A=A's age; B=B's age
\n" ); document.write( "A=3(B-(A-B))
\n" ); document.write( "A=3(2B-A)
\n" ); document.write( "A=6B-3A
\n" ); document.write( "4A=6B
\n" ); document.write( "A=6/4B
\n" ); document.write( ".
\n" ); document.write( "A+B=25
\n" ); document.write( "A=25-B
\n" ); document.write( ".
\n" ); document.write( "25-B=6/4B
\n" ); document.write( "25=10/4B
\n" ); document.write( "10=B ANSWER 1: B is 10 years old.
\n" ); document.write( ".
\n" ); document.write( "A+B=25yrs
\n" ); document.write( "A=25yrs-10yrs
\n" ); document.write( "A=15yrs ANSWER 2: A is 15 years old.
\n" ); document.write( "
\n" ); document.write( "
\n" );