document.write( "Question 980079: A told B \" I am thrice as old as you were when I was as old as you are\"... If the sum of their present ages is 25... Find their present ages...... \n" ); document.write( "
Algebra.Com's Answer #601293 by macston(5194)![]() ![]() You can put this solution on YOUR website! A=A's age; B=B's age \n" ); document.write( "A=3(B-(A-B)) \n" ); document.write( "A=3(2B-A) \n" ); document.write( "A=6B-3A \n" ); document.write( "4A=6B \n" ); document.write( "A=6/4B \n" ); document.write( ". \n" ); document.write( "A+B=25 \n" ); document.write( "A=25-B \n" ); document.write( ". \n" ); document.write( "25-B=6/4B \n" ); document.write( "25=10/4B \n" ); document.write( "10=B ANSWER 1: B is 10 years old. \n" ); document.write( ". \n" ); document.write( "A+B=25yrs \n" ); document.write( "A=25yrs-10yrs \n" ); document.write( "A=15yrs ANSWER 2: A is 15 years old. \n" ); document.write( " \n" ); document.write( " |