document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=980083>Question 980083</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Susan has 600 feet of fencing to use in making a yard for her new puppy. The yard she has planned has a length that is 75 feet less than twice the width. What are the dimensions of the yard? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #601288 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=601288\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=width; L=length=2W-75ft; P=perimeter=600ft<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "600ft=2(L+W) Divide each side by 2.<BR>\n" );
document.write( "300ft=L+W Substitute for L.<BR>\n" );
document.write( "300ft=2W-75ft+W Subtract 75 ft from each side.<BR>\n" );
document.write( "375ft=3W Divide each side by 3.<BR>\n" );
document.write( "125ft=W ANSWER 1: The width is 125 feet.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "L=2W-75ft<BR>\n" );
document.write( "L=2(125ft)-75ft<BR>\n" );
document.write( "L=250ft-75ft<BR>\n" );
document.write( "L=175ft ANSWER 2: The length is 175 feet.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "600ft=2(175ft+125ft)<BR>\n" );
document.write( "600ft=2(300ft)<BR>\n" );
document.write( "600ft=600ft<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );