document.write( "Question 980076: Sam is 8 years older than his brother. Seven years ago, Sam was twice as old as his brother. How old is sam now? \n" ); document.write( "
Algebra.Com's Answer #601282 by macston(5194)![]() ![]() You can put this solution on YOUR website! S=Sam's age; B=brother's age \n" ); document.write( ". \n" ); document.write( "S=B+8yrs Use this to substitute for S below. \n" ); document.write( ". \n" ); document.write( "S-7yrs=2(B-7yrs) Substitute for S. \n" ); document.write( "B+8yrs-7yrs=2B-14yrs Subtract B from each side. \n" ); document.write( "1yr=B-14yrs Add 14 years to each side. \n" ); document.write( "15 years=B Brother is 15 years old. \n" ); document.write( ". \n" ); document.write( "S=B+8yrs \n" ); document.write( "S=15yrs+8yrs \n" ); document.write( "S=23yrs Sam is now 23 years old. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "Seven years ago, Sam was twice as old as his brother. \n" ); document.write( "S-7yrs=2(b-7yrs) \n" ); document.write( "23yrs-7yrs=2(15yrs-7yrs) \n" ); document.write( "16yrs=2(8yrs) \n" ); document.write( "16yrs=16yrs \n" ); document.write( " |