document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=83610>Question 83610</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the period of the graph of the equation y=3cos(x/2+ pie) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60128 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60128\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The general equation is y = ACos(Bx - C) whose period is 2Pi/B\r<BR>\n" );
document.write( "\n" );
document.write( "Comparing the given function y = 3cos(x/2 + Pi) with the above, we find that B = 1/2\r<BR>\n" );
document.write( "\n" );
document.write( "Thus the period of the given function is 2PI/(1/2)\r<BR>\n" );
document.write( "\n" );
document.write( "                                       = 4Pi </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );