document.write( "Question 980061: Please help me solve
\n" ); document.write( "Find the exact value of
\n" ); document.write( "a. sin 300°
\n" ); document.write( "b. tan(405°)(Hint:405° =360° +45°)
\n" ); document.write( "c. cot (13π/3) (Hint:13π/3= 4π+π/3)
\n" ); document.write( "

Algebra.Com's Answer #601274 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first two parts to get you started.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "a)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "300 degrees is in quadrant IV. The reference angle formula for quadrant IV is\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R = 360 - x\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "where R is the reference angle and x is the given angle, so, \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R = 360 - x
\n" ); document.write( "R = 360 - 300
\n" ); document.write( "R = 60\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now use either a 30-60-90 triangle, or a unit circle to find that \"sin%2860%29+=+%28sqrt%283%29%29%2F2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Because this angle (300 degrees) is in Q4, we know sine is negative\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"sin%28300%29+=+-sin%2860%29+=+-%28sqrt%283%29%29%2F2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Final Answer: \"sin%28300%29+=+-%28sqrt%283%29%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "b)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"tan%28a%2Bb%29+=+%28tan%28a%29%2Btan%28b%29%29%2F%281-tan%28a%29%2Atan%28b%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"tan%28360%2B45%29+=+%28tan%28360%29%2Btan%2845%29%29%2F%281-tan%28360%29%2Atan%2845%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"tan%28360%2B45%29+=+%280%2B1%29%2F%281-0%2A1%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"tan%28360%2B45%29+=+%280%2B1%29%2F%281-0%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"tan%28360%2B45%29+=+1%2F1\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"tan%28360%2B45%29+=+1\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "------------------\r
\n" ); document.write( "\n" ); document.write( "So, \"tan%28360%2B45%29+=+tan%28405%29+=+1\"
\n" ); document.write( "
\n" );