document.write( "Question 980038: Find an equation of the line containing the centers of the two circles:
\n" ); document.write( "x² + y² - 10x - 10y + 49 = 0 and x² + y² - 4x - 6y + 9 = 0.
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\n" ); document.write( "a. -2x - 3y + 5 = 0
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\n" ); document.write( "b. 2x + 3y + 5 = 0
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\n" ); document.write( "c. 8x - 7y + 5 = 0
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\n" ); document.write( "d. 2x - 3y + 5 = 0
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Algebra.Com's Answer #601242 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
an equation of the line containing the centers of the two circles: \r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+y%5E2+-+10x+-+10y+%2B+49+=+0\" ...........complete squares and write equation of a circle in a form \"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\"
\n" ); document.write( "\"%28x%5E2+-+10x%2Bb%5E2%29+-b%5E2%2B+%28y%5E2+-+10y%2Bb%5E2%29+-b%5E2%2B+49+=+0\"\r
\n" ); document.write( "\n" ); document.write( "....recall, \"%28a-b%29%5E2=a%5E2-2ab%2Bb%5E2\"
\n" ); document.write( "in your case \"%28x%5E2+-+10x%2Bb%5E2%29\", \"a=1\" and \"2ab=10\", so we have \"2%2A1%2Ab=10\"=>\"2b=10\"=>\"b=5\"\r
\n" ); document.write( "\n" ); document.write( "and we can write\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2+-+10x%2B5%5E2%29+-5%5E2%2B+%28y%5E2+-+10y%2B5%5E2%29+-5%5E2%2B+49+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-+5%29%5E2+-25%2B+%28y+-+5%29%5E2+-25%2B+49+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-+5%29%5E2+%2B+%28y+-+5%29%5E2+-50%2B+49+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-+5%29%5E2+%2B+%28y+-+5%29%5E2+-1+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-+5%29%5E2+%2B+%28y+-+5%29%5E2++=+1\"\r
\n" ); document.write( "\n" ); document.write( "as you can see, \"h=5\",\"k=5\", and \"r=1\"\r
\n" ); document.write( "\n" ); document.write( "so, the center is at (\"5\",\"5\")\r
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\n" ); document.write( "\n" ); document.write( "now do same with other circle:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+y%5E2+-+4x+-+6y+%2B+9+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2++-+4x%2Bb%5E2%29-b%5E2%2B+%28y%5E2+-+6y+%2Bb%5E2%29-b%5E2%2B+9+=+0\"......\"2ab=4\"=>\"2%2A1%2Ab=4\"=>\"b=2\" and for \"y\" we have \"2ab=6\"=>\"2%2A1%2Ab=6\"=>\"b=3\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2++-+4x%2B2%5E2%29-2%5E2%2B+%28y%5E2+-+6y+%2B3%5E2%29-3%5E2%2B+9+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x++-+2%29%5E2-4%2B+%28y+-+3%29%5E2-9%2B+9+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x++-+2%29%5E2%2B+%28y+-+3%29%5E2-4+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x++-+2%29%5E2%2B+%28y+-+3%29%5E2=+4\"\r
\n" ); document.write( "\n" ); document.write( "as you can see, \"h=2\",\"k=3\", and \"r=2\"\r
\n" ); document.write( "\n" ); document.write( "so, the center is at (\"2\",\"3\")\r
\n" ); document.write( "\n" ); document.write( "now we have two points, (\"5\",\"5\") and (\"2\",\"3\"), and we can find the equation of a line passing through these two points\r
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Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (5, 5) and (x2, y2) = (2, 3).
\n" ); document.write( " Slope a is .
\n" ); document.write( " Intercept is found from equation \"a%2Ax%5B1%5D%2Bb+=+y%5B1%5D\", or \"0.666666666666667%2A5+%2Bb+=+1.66666666666667\". From that,
\n" ); document.write( " intercept b is \"b=y%5B1%5D-a%2Ax%5B1%5D\", or \"b=5-0.666666666666667%2A5+=+1.66666666666667\".
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\n" ); document.write( " y=(0.666666666666667)x + (1.66666666666667)
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\n" ); document.write( " Your graph:
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\n" ); document.write( "\n" ); document.write( "since your line is \"y=0.666666666666667x+%2B+1.66666666666667\"\r
\n" ); document.write( "\n" ); document.write( "or \"y=%282%2F3%29x+%2B+5%2F3\", we can multiply both sides by \"3\"\r
\n" ); document.write( "\n" ); document.write( "\"3y=3%282%2F3%29x+%2B+3%285%2F3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"3y=2x+%2B+5\", in standard form will be\r
\n" ); document.write( "\n" ); document.write( "\"2x-3y%2B5=0\"\r
\n" ); document.write( "\n" ); document.write( "so, your answer is:\r
\n" ); document.write( "\n" ); document.write( "d. \"2x+-+3y+%2B+5+=+0\"\r
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