document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=980028>Question 980028</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ratio of length,breath and height of a room is 5:4:2. If area of four walls is 144 sq. metres.Find diagonal of the room? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #601230 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=601230\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ratio to add to 144 is some x, 5x:4x:2x ;; x units are meters.\r<BR>\n" );
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document.write( "One pair of walls has area 2*10x^2)=20x^2 m^2<BR>\n" );
document.write( "The other pair of walls has area 2*8x^2=16x^2 m^2<BR>\n" );
document.write( "If x=2, one pair has area 80; the other has area 64 m^2<BR>\n" );
document.write( "Therefore the ratio in the room is 10:8:4 m.\r<BR>\n" );
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document.write( "The floor is 10 x 8 with diagonal sqrt (100+64)=sqrt (164).  Don't reduce it.\r<BR>\n" );
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document.write( "The room diagonal uses the floor diagonal as one leg, and the height as a second leg.  The diagonal across the room is the square root of each of those squared.\r<BR>\n" );
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document.write( "The first is 164, the height is 16, and their sum is 180.<BR>\n" );
document.write( "Take the square root of (180 m^2), and the answer is 6 sqrt(5) m or 13.4 meters. </SPAN>\n" );
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