document.write( "Question 980019: there are 45 coins in a jar. the probability of drawing a coin randomly that is not a dime is 11/15. how many nickels should be added to have the probability of drawing a dime to be 2/9?\r
\n" ); document.write( "\n" ); document.write( "the probability of drawing a yellow marble from a bag with 42 marbles is 2/3. how many orange marbles should be taken away to have the probability of drawing a yellow marble from the bag to be 14/15?\r
\n" ); document.write( "\n" ); document.write( "there is a stack of folders. the probability of drawing out a yellow folder from the stack is 7/12. after 18 yellow folders are taken out, the probability of drawing out a yellow folder is 4/9. how many yellow folders are there initially?\r
\n" ); document.write( "\n" ); document.write( "there are 9 girls in a team. if 6 boys joined the team then the probability of choosing a boy from the team is 4/7. what is the probability of choosing a boy from the team before the six boys join the team?\r
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Algebra.Com's Answer #601223 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
If 11/15 chance a coin isn't a dime, there is a 4/15 chance it is, and with 45 coins, there are 12 dimes.\r
\n" ); document.write( "\n" ); document.write( "Let x=number of nickels\r
\n" ); document.write( "\n" ); document.write( "12/(45+x) =2/9
\n" ); document.write( "Cross-multiply
\n" ); document.write( "90+2x=108
\n" ); document.write( "2x=18
\n" ); document.write( "x=9\r
\n" ); document.write( "\n" ); document.write( "9 nickels
\n" ); document.write( "54 coins in bag, 12 are dimes. Therefore, probability of drawing a dime is 12/54=2/9
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\n" ); document.write( "There are 28 yellow marbles out of 42
\n" ); document.write( "28/(42-x) = 14/15; x = orange marble number;
\n" ); document.write( "cross-multiply\r
\n" ); document.write( "\n" ); document.write( "588-14x=420
\n" ); document.write( "-14x=-168
\n" ); document.write( "x=12 orange marbles must be removed
\n" ); document.write( "bag now has 30 marbles with 28 of them yellow. That is 14/15
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\n" ); document.write( "x=multiple of numerator and denominator.
\n" ); document.write( "(7x/12x)= fraction of number of folders that are yellow.
\n" ); document.write( "(7x-18)/(12x-18) = 4/9
\n" ); document.write( "cross multiply
\n" ); document.write( "48x-72=63x-162; collect like terms on same side, will both be positive or both be negative
\n" ); document.write( "-15x=-90
\n" ); document.write( "x=6
\n" ); document.write( "12x=12*6=72 folders
\n" ); document.write( "(7/12) or 42 folders are yellow
\n" ); document.write( "remove 18 yellow folders and have 24 yellow folders/54 (72-18) total.
\n" ); document.write( "24/54=4/9, if you divide numerator and denominator by 6.
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\n" ); document.write( "team originally had 9 girls +x boys.
\n" ); document.write( "now the team has 9 girls and (6+x) boys, or 15+x total members
\n" ); document.write( "probability of choosing a boy is (6+x)/(15+x) =(4/7)
\n" ); document.write( "cross-multiply
\n" ); document.write( "60+4x=42+7x
\n" ); document.write( "18=3x
\n" ); document.write( "x=6
\n" ); document.write( "The team originally had 15 members, 6 boys, and the probability of choosing a boy was 6/15=2/5. This is the answer.
\n" ); document.write( "Now the team has 21 members, 12 boys, and the probability of choosing a boy is 12/21=(4/7)
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