document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=980004>Question 980004</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, I'm currently studying for my accuplacer by using some study guides online that also provide a test at the end.  I'm currently practicing factoring trinomials and on my test I got three answers wrong, which the answers seem to just be written in a different form than mine, but using foil on MY answers comes up with the original trinomial as well, so it would seem to be correct.<BR>\n" );
document.write( "Long story short, I'm curious if I did something wrong, or simply came up with another viable solution and if my answer would be acceptable, say on a test.  I'd like to provide all three questions just to clarify, but I understand the one problem rule, so please feel free to only address the first one, or give a simple yes or no if my answers would be acceptable.\r<BR>\n" );
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document.write( "First one: 21 + 4k^2 + -1k^4\r<BR>\n" );
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document.write( "What I came up with:  -1(k^2 + 3)(k^2 + -7)<BR>\n" );
document.write( "What they came up with: (3 + k^2)(7 + -1k^2)\r<BR>\n" );
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document.write( "Second one:  21 + 4k^2 + -1k^4\r<BR>\n" );
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document.write( "What I came up with:  -1(k^2 + 3)(k^2 + -7)<BR>\n" );
document.write( "What they came up with: (3 + k^2)(7 + -1k^2)\r<BR>\n" );
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document.write( "Third one:  3 + -10r^2 + 8r^4\r<BR>\n" );
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document.write( "What I came up with:  (2r^2 + -1)(4r^2 + -3)<BR>\n" );
document.write( "What they came up with: (1 + -2r^2)(3 + -4r^2)\r<BR>\n" );
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document.write( "Sorry if this is confusing, I just mainly want to know if my answer is ALSO acceptable, and if it's not, what method you used to come up with the \"correct\" answer they provided. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #601220 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=601220\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First one: 21 + 4k^2 + -1k^4\r<BR>\n" );
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document.write( "What I came up with:  -1(k^2 + 3)(k^2 + -7)<BR>\n" );
document.write( "What they came up with: (3 + k^2)(7 + -1k^2)<BR>\n" );
document.write( "These are the same.  -1*(k^2 - 7) = (7 - k^2)<BR>\n" );
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document.write( "Second one:  21 + 4k^2 + -1k^4\r<BR>\n" );
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document.write( "What I came up with:  -1(k^2 + 3)(k^2 + -7)<BR>\n" );
document.write( "What they came up with: (3 + k^2)(7 + -1k^2)<BR>\n" );
document.write( "Same again, same reason.<BR>\n" );
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document.write( "Third one:  3 + -10r^2 + 8r^4\r<BR>\n" );
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document.write( "What I came up with:  (2r^2 + -1)(4r^2 + -3)<BR>\n" );
document.write( "What they came up with: (1 + -2r^2)(3 + -4r^2)<BR>\n" );
document.write( "Same thing here, except both binomials are multiplied by -1.<BR>\n" );
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document.write( "Your format is what's usually expected, in descending order of exponents.<BR>\n" );
document.write( "Third one:  3 + -10r^2 + 8r^4 = 8r^4 - 10r^2 + 3<BR>\n" );
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document.write( "What I came up with:  (2r^2 + -1)(4r^2 + -3) --> (2r^2 - 1)*(4r^2 - 3)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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