document.write( "Question 979991: Please help me here. Illustrate and solve this problem. Thank you :)
\n" ); document.write( "A PAL plane takes off from Manila International Airport at an angle of 10°40'. How high will it be after it has flown a horizontal distance of 1800 meters.
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Algebra.Com's Answer #601205 by ikleyn(52847)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "You know the horizontal distance  L = 1800 meters.
\n" ); document.write( "It is the leg of a right-angled triangle.\r
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\n" ); document.write( "\n" ); document.write( "And you also know the angle  \"alpha\" = 10°40'.
\n" ); document.write( "It is the angle of the right-angled triangle.\r
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\n" ); document.write( "\n" ); document.write( "You need to find the other leg of the right-angled triangle  h,  which is the height  (the altitude).\r
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\n" ); document.write( "\n" ); document.write( "Use the Trigonometry function  tangent:   \"h\" = \"L\".\"tan%28alpha%29\" = 1800*tan(10°40') . . . \r
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\n" ); document.write( "\n" ); document.write( "Please complete yourself these calculations.\r
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\n" ); document.write( "\n" ); document.write( "Good luck!\r
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