document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=979963>Question 979963</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation on the interval [0,2pi)<BR>\n" );
document.write( "4sec^2x-8=0<BR>\n" );
document.write( "Type an exact answer in terms of pi. Use a comma to separate answers as needed. Use integers or fractions for any numbers in the expressions. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #601185 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=601185\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4 sec^2 x=8<BR>\n" );
document.write( "sec^2 x=2<BR>\n" );
document.write( "sec x = +/- sqrt (2)\r<BR>\n" );
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document.write( "sec x is 1/cos x<BR>\n" );
document.write( "Therefore sqrt 2=1/cos x; cos x=1/sqrt(2) or sqrt (2)/2<BR>\n" );
document.write( "That occurs at 45 degrees (pi /4) and all around the 0, 2 pi interval, since it is +/-\r<BR>\n" );
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document.write( "pi/4<BR>\n" );
document.write( "3 pi/4<BR>\n" );
document.write( "5pi/4<BR>\n" );
document.write( "7 pi/4<BR>\n" );
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