document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=979956>Question 979956</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cone is sliced in half such that the face created is an equilateral triangle with side of length 4. Find the volume of the half cone </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #601182 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39800)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=601182\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Diameter of the cone's circular base is 4, so the radius is 2.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The cone height becomes the longer leg of a 30-60-90 triangle with hypotenuse 4, small leg 2, and that longer leg for the cone height, h.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "r=2, to use in volume  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h%2Api%2Ar%5E2 ALIGN=MIDDLE  ALT=\"h%2Api%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%5E2%2Bh%5E2=4%5E2 ALIGN=MIDDLE  ALT=\"2%5E2%2Bh%5E2=4%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Solve for h;<BR>\n" );
document.write( "use it in the volume expression and evaluate volume. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );