document.write( "Question 979923: I have used 129 hours of the 350 hours that I can use to record tv on my cable account. I figured out that I could record 442 1/2 hour shows. What I want to find out is if I wanted to record 73 hour shows and the rest 1/2 hour shows, how do I calculate and show in linear inequality in both a graph and righting it out step by step?\r
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document.write( "Thank you,
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document.write( "Lisa \n" );
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Algebra.Com's Answer #601155 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! I have used 129 hours of the 350 hours that I can use to record tv on my cable account. I figured out that I could record 442 1/2 hour shows. What I want to find out is if I wanted to record 73 hour shows and the rest 1/2 hour shows, how do I calculate and show in linear inequality in both a graph and righting it out step by step? \n" ); document.write( "--------------------------- \n" ); document.write( "73*1 + n*(1/2) <= 350 \n" ); document.write( "n/2 = 277 \n" ); document.write( "n = 554 30 minute shows \n" ); document.write( "---------------------- \n" ); document.write( "If you're only concerned with 1 hr and 1/2, count the 1 hour as 2 shows. \n" ); document.write( "Then you can graph shows vs. time. \n" ); document.write( "==================== \n" ); document.write( "That's a lot of shows. When will you have time to watch them all? \n" ); document.write( " \n" ); document.write( " |