document.write( "Question 979875: A train leaves Los Angeles at 2 pm heading north at 50mph. If the next rain leaves in 3 hours, and will also head north at 60mph, at what time will they meet? \r
\n" ); document.write( "\n" ); document.write( "** Can u please write all the steps and not only the answer. That would help me understand a lot better. Thanks guys!
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Algebra.Com's Answer #601128 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
First, you want to know how much of a
\n" ); document.write( "head start the 1st train got
\n" ); document.write( "\"+d%5B1%5D+=+50%2A3+\"
\n" ); document.write( "\"+d%5B1%5D+=+150+\" mi is the 1st train's head start
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\n" ); document.write( "Now you want to start a stop watch when the
\n" ); document.write( "2nd train leaves at 2 PM + \"+3+\" hrs = 5 PM
\n" ); document.write( "Let \"+t+\" = the time on the stopwatch when
\n" ); document.write( "the 2nd train catches up with the 1st train
\n" ); document.write( "( note that both trains will travel for the
\n" ); document.write( "same amount of time as shown on stop watch )
\n" ); document.write( "Let \"+d+\" = the distance the 2nd train travels
\n" ); document.write( "until it catches the 1st train
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\n" ); document.write( "Equation for 1st train:
\n" ); document.write( "(1) \"+d+-+150+=+50t+\"
\n" ); document.write( "Equation for 2nd train:
\n" ); document.write( "(2) \"+d+=+60t+\"
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\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) \"+60t+-+150+=+50t+\"
\n" ); document.write( "(1) \"+10t+=+150+\"
\n" ); document.write( "(1) \"+t+=+15+\"
\n" ); document.write( "The trains will meet \"+15+\" hrs after 5 PM
\n" ); document.write( "\"+12+\" hrs after 5 PM = 5 AM, and
\n" ); document.write( "5 AM + \"+3+\" = 8 AM the following day
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\n" ); document.write( "check anwer:
\n" ); document.write( "(2) \"+d+=+60t+\"
\n" ); document.write( "(2) \"+d+=+60%2A15+\"
\n" ); document.write( "(2) \"+d+=+900+\" mi
\n" ); document.write( "and
\n" ); document.write( "(1) \"+d+-+150+=+50t+\"
\n" ); document.write( "(1) \"+d+-+150+=+50%2A15+\"
\n" ); document.write( "(1) \"+d+=+750+%2B+150+\"
\n" ); document.write( "(1) \"+d+=+900+\" mi
\n" ); document.write( "OK
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