document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=979808>Question 979808</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (24x^3y^4)^1/2 + (54xy^2)^1/2 = \r<BR>\n" );
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document.write( "Assuming x and y are positive real numbers <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #601068 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=601068\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 sqrt (6) x^(3/2)y^2 + 3 sqrt (6) x^(1/2) y.  One takes the square root of each part, the number and each variable.  sqrt (24)=sqrt(4)*sqrt (6); sqrt (54)=sqrt (9)*sqrt(6) or 3sqrt(6)\r<BR>\n" );
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document.write( "Factor out x^(1/2)y [sqrt(6)]\r<BR>\n" );
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document.write( "x^(1/2) y  sqrt(6) {2 xy+3} </SPAN>\n" );
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